list - Sort depending on variable in Scala -
is there way in scala sort list of objects specific field using variable set order (asc or desc)? i know sortwith can like mylist.sortwith((x, y) => x < y) or mylist.sortwith((x, y) => x > y) to sort ascending or descending, want use variable. so, tried this: case class person(firstname: string, lastname: string, age: int) private def sortdocuments(sortfield: string, sortdirection: string, people: list[person]): list[person] = { sortfield match { case "age" => people.sortby(if (sortdirection == "desc") -_.age else _.age) case "firstname" => people.sortwith { sortstring(a.firstname, b.firstname, sortdirection) } case "lastname" => people.sortwith { sortstring(a.firstname, b.lastname, sortdirection) } } } private def sortstring(fielda: string = null, fieldb: string = null, direction: string = "asc") = { val fieldavaild = option(fielda).getorelse("") val fieldbvaild =
