c - Store argv to an int array -

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i have code store argv dynamically allocated int array:

int *data;    // pointer array of integer numbers int size;     // size of data array  int main(int argc, char* argv[]) {   // initialize array data   size=argc;   printf("%dsize=\n",size);   printf("%d\n",argc);   data=(int*)calloc(size,sizeof(int));   int i=0;   (i=1;i<size;i++)   {    data[i]=argv[i];    printf("%d\n",data[i]);   }   (i=1;i<argc;i++)   {    printf("%d\n",argv[i]);   }   return 0; }

when run in command line: ./sumprime 5 1 2 3 4 prints:

6size= 6 15311660 15311662 15311664 15311666 15311668 15311660 15311662 15311664 15311666 15311668

not array of 5 1 2 3 4 expected. how can store int array argv , print out?

should be:

   data[i]=atoi(argv[i]);

remember command line argument strings. though pass integer in command line string needs converted integer.


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