python - Why do I get a syntax error? -

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sales = 1000  #def commissionrate():    if (sales < 10000):     print("da")   else:     if (sales <= 10000 , >= 15000):         print("ea")

syntax error on if (sales <= 10000 , >= 15000): line. particularly on equal signs.

you need compare sales against second condition also:

in [326]:  sales = 1000 ​ #def commissionrate(): ​ ​ if (sales < 10000):     print("da") else:     if (sales <= 10000 , sales >= 15000):         print("ea") da

you need this: 

if (sales <= 10000 , sales >= 15000):                        ^^^^ sales here

additionally don't need parentheses () around if conditions:

if sales <= 10000 , sales >= 15000:

works fine

you rewrite more compact:

in [328]:  sales = 1000 ​ if sales < 10000:     print("da") else:     if 10000 <= sales <= 15000:         print("ea") da

so if 10000 <= sales <= 15000: works also, @donkey kong

additionally (thanks @pjz) , nothing code logically sales cannot both less 10000 , greater 15000.

so without syntax errors condition never true.

you wanted if sales > 10000 , sales <= 15000: or if 10000 <= sales <= 15000: maybe clearer you

just expand on if 10000 <= sales <= 15000: syntax (thanks @will suggestion), in python 1 can perform math comparisons lower_limit < x < upper_limit explained here more natural usual if x > lower_limit , x < upper_limit:.

this allows comparisons chained, docs:

formally, if a, b, c, ..., y, z expressions , op1, op2, ..., opn comparison operators, a op1 b op2 c ... y opn z equivalent a op1 b , b op2 c , ... y opn z, except each expression evaluated @ once.


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