bash - Delete <feff> from text file, UTF 8 -

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i use bash script filter text 1 text file another. text encoded in utf 8.

#!/bin/bash mid=$1 infile="/var/www/tmp/textgrid_uploads/${mid}.txt" outfile="/home/var/www/vids/$mid/${mid}_textgrid.mlf" tmpfile="/home/var/www/vids/$mid/${mid}.tmp"  i=1  touch $tmpfile  cat $infile | grep "text =" | cut -d '"'  -f2 | tr -d ',' | tr -d '.' |  tr -d ':' |  tr -d ';' |  tr -d '!' | tr -d '?' > $tmpfile #| awk '{ print tolower($0) }'  #cat $infile  | grep -v "<" | egrep -v '^[[:space:]]*$' | tr -d '.' | tr -d "," | tr -d ";" | tr -d ":" | tr -d "^" | tr -d '#' | tr -d '?' | tr -d '!' | tr -d '%' | tr -d '@' | tr -d '*' | tr -d '~' | grep -v '((xxxxx))' | awk '{ print tolower($0) }' > $tmpfile  #cat $infile | grep -v 'webvtt' | grep -v "\--" | grep -v '^$' | sed 's/?/./g' | sed 's/!/./g' | tr -d '.' | tr -d "," | tr -d ";" | tr -d ":" | awk '{ print tolower($0) }' > $tmpfile  nlines=$(cat $tmpfile | wc -l)  echo "#!mlf!#" >> $outfile echo "\"*/dummyfile.lab\"" >> $outfile   while [ $i -le $nlines ]         line=$(cat $tmpfile | sed $i'q;d') #zobrazi konkretny riadok         printf '%s\n' $line | sed '/^\s*$/d' | cut -d "/" -f1 | egrep -v '^[[:space:]]*$' >> $outfile #zapis po riadkoch s odstranenim znaciek         i=$[$i+1] #pocitadlo done echo "."  >> $outfile  rm $tmpfile

output of script is:

#!mlf!#  "*/dummyfile.lab"   <feff> v utorok o devätnástej bude vo fejs

i want remove first word feff both brackets. please give me whole example how it. new in bash , use script didn't create it. guys.


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